I am trying to get a co-ordinate on the outer circle, by knowing the initital angle and how far out (1+h) is it. The outer circel is a result of the distance away it is. So using the initial angle and the distance (1+h) I am trying to get a set of co-ordinates for the location. My initial thought was (as in the image) to say [cos(v)+h ; sin(v)+h] But thinking about it a second time, I doubt that it's do-able like that. I thought about using tangent instead, by saying tan(A)= Sin(A)/Cos(A) but I am not sure, what I am exactly getting a result of using that, since I have little experience with tan. Anyone got an idea on how I solve this?
EDIT: The co-ordinate I am trying to find, is the point on the outer circle, at a given angle (v) and at a distance away at x=1+h
You shouldn't be adding h. The radius of the outer circle is the number of unit circles outward from 0. One unit circle is x=cos(angle), y = sin(angle).
You desire h unit circles, where h is the radius of the outer circle.
Multipling the outer radius with the value of the sinus and cosnius result, sounds logic. Just a question to that, by multiplying with the outer circle, do you mean multiply by the scale difference eg. 1.50 for a circle at 1.50 radius? The reason I used 1+h was to symbolise an increment of h from the original circle of one, thus the equation that the x co-ordinate of the final point would be x=1+h. Sorry if it sounded way of, I was translating every term to English, without knowing what the exact words was in English, and the +h concept was stolen from a f(x)+h-f(x) differentiale calculation. Anyhow, thanks for the help.
You have a point that is some distance from the center of a circle. You know the direction that point is from the center, and you know how far the point is from the center. What you don't know is the x and y coordinates of this point. Is that correct?
If so, you should multiply the sin and cos by the radius of the outer circle. When you say 1+h, I believe you are referring to the radius of the outer circle.
Cos(angle) gives you the x-coordinate of a point on a circle of radius 1. r*cos(angle) gives you the x-coordinate of a point on a circle of radius r. Likewise for r*Sin(angle).
I am trying to get a co-ordinate on the outer circle, by knowing the initital angle and how far out (1+h) is it. The outer circel is a result of the distance away it is. So using the initial angle and the distance (1+h) I am trying to get a set of co-ordinates for the location. My initial thought was (as in the image) to say [cos(v)+h ; sin(v)+h] But thinking about it a second time, I doubt that it's do-able like that. I thought about using tangent instead, by saying tan(A)= Sin(A)/Cos(A) but I am not sure, what I am exactly getting a result of using that, since I have little experience with tan. Anyone got an idea on how I solve this?
EDIT: The co-ordinate I am trying to find, is the point on the outer circle, at a given angle (v) and at a distance away at x=1+h
@Deeweext: Go
Multiply the radius of the outer circle by the sin and cos of the angle.
The x coordinate would be distance*cos(angle), and the y would be distance*sin(angle).
x=1+h? or distance = 1+h? dont use x if u dont mean it.
@Deeweext: Go
You shouldn't be adding h. The radius of the outer circle is the number of unit circles outward from 0. One unit circle is x=cos(angle), y = sin(angle).
You desire h unit circles, where h is the radius of the outer circle.
If the center of the circle is the center of the axises, the right way way would be to multiply the vector of the location in the inner circle by 1+h
@tFighterPilot: Go
What I said is not incorrect. You are all overcomplicating the concept.
@Vexal: Go
Multipling the outer radius with the value of the sinus and cosnius result, sounds logic. Just a question to that, by multiplying with the outer circle, do you mean multiply by the scale difference eg. 1.50 for a circle at 1.50 radius? The reason I used 1+h was to symbolise an increment of h from the original circle of one, thus the equation that the x co-ordinate of the final point would be x=1+h. Sorry if it sounded way of, I was translating every term to English, without knowing what the exact words was in English, and the +h concept was stolen from a f(x)+h-f(x) differentiale calculation. Anyhow, thanks for the help.
@Deeweext: Go
You have a point that is some distance from the center of a circle. You know the direction that point is from the center, and you know how far the point is from the center. What you don't know is the x and y coordinates of this point. Is that correct?
If so, you should multiply the sin and cos by the radius of the outer circle. When you say 1+h, I believe you are referring to the radius of the outer circle.
Cos(angle) gives you the x-coordinate of a point on a circle of radius 1. r*cos(angle) gives you the x-coordinate of a point on a circle of radius r. Likewise for r*Sin(angle).
@Vexal: Go
Yeah as I understood it. Again thanks.